@lissyx I am generating my CSVs using a python script and I encoded it in ‘UTF-8’. Even that didn’t help
lissyx
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I already told you how to fix it. Change the code that shows the KeyError, print the hex code of the character, I’m sure your “3” is not the 0x33 one, but rather some other UTF-8 code. And you don’t have this one in your alphabet. Hence the error.
The error is in label_from_string() in text.py. I have printed hex(int(string)) but this is giving me the same value in hex as well i.e ‘0x03’. I had to convert this to int because the input is string and hex() doesn’t work with string. Next, I tried printing every string (which is actually a character) which goes in this function. Again, that didn’t help as I started getting some python threading error. I am not sure how to proceed further now.
lissyx
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