Problem with double assignment operator?

MDN Learn
#1

const people = [‘Chris’, ‘Anne’, ‘Colin’, ‘Terri’, ‘Phil’, ‘Lola’, ‘Sam’, ‘Kay’, ‘Bruce’];
let refused, admitted;

it seems that the first row below is broken because it return undefined I would like to know why any idea? thanks

refused = document.querySelector(’.refused’).textContent = "Refused: "; // some problem with double assignment operator ?
console.log(refused.textContent); // OUTPUT UNDEFINED but why?
admitted = document.querySelector(’.admitted’); // with separete expression gives no problem but I need to continue to type varName.textcontent and its a bit long :wink:

admitted.textContent = 'Admit: ';

for (let i = 0; i < people.length; i ++) {

if (people[i] == “Phil” || people[i] == “Lola”) {
refused += people[i]+’, ';

} else {
admitted.textContent += people[i]+’, ';
}

}

admitted.textContent = admitted.textContent.slice(0,admitted.textContent.length-2)+’.’;

refused = refused.slice(0,refused.length-2)+’.’;

#2

Yeah, there’s a problem with

refused = document.querySelector(’.refused’).textContent = "Refused: ";

You have to do them in separate steps, e.g.

const admitted = document.querySelector('.admitted');
const refused = document.querySelector('.refused');

admitted.textContent = 'Admit: ';
refused.textContent = 'Refuse: '