Hi, chris Please explain how iteration work I am not able to uderstand how looping work, In both ,when use isPrime(num) and when use while(!isPrime(i)) . I just want to know how iteration work I mean looping. how i increase and how decrease. for find prime. I hope you help me.
function isPrime(num) {
for(let i=2;i<num;i++) { // here how ‘i’ will work
if(num % i === 0) {
return false;
}
}
return true;
}
// Add your code here
while(i>=2) {
if(!isPrime(i)) { // and also how ‘i’ here is work
i–;
continue;
}
para.textContent += ${i} ;
i–;
}
Hello @alishamsher98
for(let i=2;i<num;i++)
- this line create variable called i and it’s value
2)then the loop will test if i<num if true then it will make iterate one timewhich mean it do the loop body
if(num % i === 0) {
return false; // if num %2i will be 0 then this return line will return and exit the function which mean it will exit the loop also
- after one cycle of the loop i++ willl be excute and it increase i by 1
- the loop do the test part which is i<num if true it will continu
- it will keep repeat step 2 ,3,4 till the i<num turn to false and of course that the internal if statment does not exit the function the one i mentioned in step 2
if the loop end and normaly by i<num lead to false then the function return true
for the while loop
- i will be tested first if it >=2 or not if yes then the while body will be excuted if not then the while loop would work at all
- first it will check if i isprime by calling the isPrime function with i as parameter
- it will test if !isPrime(i) that mean the oposite of the return of the function
- if step 3 lead to true i will be decresed by 1
- continue mean it will go to the while test part which is i>=2 without continue the while body
6)if step 3 lead to false it will do this para.textContent += ${i} ;
then decrement i by 1
hope that help and have a nice day 
}
}
i++ will increament
1 Like
Thankyou… You really explain concept in very well.